Study · Mathematics
Solid Geometry
Solid Geometry
Space lines and planes, and surface area / volume of prisms, pyramids, cylinders, cones and spheres.
1
lessons in this chapter
0
previous exam questions
3 hr
suggested study time
Hard
chapter difficulty
Last reviewed Sep 2026 · GetCSCA editors
Study order
Work the lessons top to bottom — each ends with practice, a timed set and a 5-stage drill. Then prove it in a full 48Q mock.
Solid Geometry
Lesson 1 · target ~75s per question
Positions of lines and planes in space, projections, and volume/surface-area formulas for common solids.
Why CSCA tests this
Key points — memorize
- Classify space relations first: two lines are parallel, intersecting, or skew; a line is parallel to, contained in, or intersecting a plane.
- Memorize the volume ladder: prisms/cylinders V = Bh, pyramids/cones V = Bh/3, sphere V = 4πr³/3 with surface 4πr².
- Cut cross-sections through the axis or key vertices to reduce cones, cylinders, and pyramids to triangles and rectangles.
- A line is perpendicular to a plane if it is perpendicular to two intersecting lines in that plane — the standard perpendicularity test.
- Distinguish lateral area (sides only) from total surface (plus bases), and keep area vs volume units separate.
Formula sheet
- Prism/cylinder: V = Bh
- Pyramid/cone: V = Bh/3
- Sphere: V = 4πr³/3; S = 4πr²
- Cylinder lateral area: 2πrh; cone lateral area: πrl
- a² + b² + c² = space diagonal² of a box
- Pyramid/cone total surface = base area + lateral area; prism/cylinder total = 2B + lateral
- Cone slant height: l = √(r² + h²)
- Cross-section through the axis reduces cone/cylinder to an isosceles triangle/rectangle
Classic traps
- Forgetting the /3 on pyramid/cone volumes, or applying it to prisms/cylinders.
- Using vertical height h where slant height l = √(r² + h²) is needed for cone lateral area πrl.
- Confusing skew lines with parallel ones — skew lines never meet and are not parallel.
- Reporting area units for volume (or vice versa) after multi-step computation.
Exam tactic
Worked examples
Example 1: Find the volume of a cone with r = 3 and h = 4.
- V = πr²h/3 = π · 9 · 4/3 = 12π.
Answer: 12π
Example 2: A box is 3 × 4 × 12. Find its space diagonal.
- d = √(3² + 4² + 12²) = √(9 + 16 + 144) = √169.
Answer: 13
Previous exam questions
Real CSCA-style questions tagged to Solid Geometry — answer right here.
No previous-exam questions tagged here yet.
Related guides
- 30-day study plan → fit this chapter into a week-by-week system
- 75-second pacing rule → hold 75s/question once the content clicks
- Top 10 mistakes → the error patterns that cost the most points
1 lessons · one chapter
Finished Solid Geometry? Prove it.
Run a timed set, clear every mistake, then take a full 48Q mock.